Since both potential energy and kinetic energy are equal, we can equate them. So let's say that the Given data the height from the ground h = 7 m. And so we just need to solve ), 0, equals, start fraction, 1, divided by, 2, end fraction, left parenthesis, minus, 9, point, 81, start fraction, start text, space, m, end text, divided by, start text, space, s, end text, squared, end fraction, right parenthesis, t, squared, plus, left parenthesis, 18, point, 3, start text, space, m, slash, s, end text, right parenthesis, t, minus, 12, point, 2, start text, space, m, end text, start text, left parenthesis, P, u, t, space, i, t, space, i, n, t, o, space, t, h, e, space, f, o, r, m, space, o, f, space, t, h, e, space, q, u, a, d, r, a, t, i, c, space, e, q, u, a, t, i, o, n, point, right parenthesis, end text, a, t, squared, plus, b, t, plus, c, equals, 0, t, equals, start fraction, minus, b, plus minus, square root of, b, squared, minus, 4, a, c, end square root, divided by, 2, a, end fraction, a, equals, start fraction, 1, divided by, 2, end fraction, left parenthesis, minus, 9, point, 81, start fraction, start text, space, m, end text, divided by, start text, space, s, end text, squared, end fraction, right parenthesis, b, equals, 18, point, 3, start text, space, m, slash, s, end text, c, equals, minus, 12, point, 2, start text, space, m, end text, t, equals, start fraction, minus, 18, point, 3, start text, space, m, slash, s, end text, plus minus, square root of, left parenthesis, 18, point, 3, start text, space, m, slash, s, end text, right parenthesis, squared, minus, 4, open bracket, start fraction, 1, divided by, 2, end fraction, left parenthesis, minus, 9, point, 81, start fraction, start text, space, m, end text, divided by, start text, space, s, end text, squared, end fraction, right parenthesis, left parenthesis, minus, 12, point, 2, start text, space, m, end text, right parenthesis, close bracket, end square root, divided by, 2, open bracket, start fraction, 1, divided by, 2, end fraction, left parenthesis, minus, 9, point, 81, start fraction, start text, space, m, end text, divided by, start text, space, s, end text, squared, end fraction, right parenthesis, close bracket, end fraction, t, equals, 0, point, 869, start text, space, s, end text, t, equals, 2, point, 86, start text, space, s, end text, 3, point, 20, start fraction, start text, space, m, end text, divided by, start text, space, s, end text, squared, end fraction, v, start subscript, 0, end subscript, equals, 23, point, 4, start text, space, m, slash, s, end text, a, equals, minus, 3, point, 20, start fraction, start text, space, m, end text, divided by, start text, space, s, end text, squared, end fraction, delta, x, equals, 50, point, 2, start text, space, m, end text, v, start subscript, x, end subscript, squared, equals, v, start subscript, 0, x, end subscript, squared, plus, 2, a, start subscript, x, end subscript, delta, x, (Startwiththefourthkinematicformula. In vertical motion, the distance traveled by the body is equal to the height where the body begins to move. what is that maximum height based on all of the information PDF Simplified Method for Estimating the Flight Performance of A Hobby Rocket The resulting equation reads as follows: Since the vertical velocity is zero when a projectile reaches its maximum altitude (an object thrown upward always reaches zero velocity at the peak of its trajectory), the value for vf is zero. In L. glaberrima, the relationship between mass and terminal velocity was weaker, with a 0.1 mg increase in mass corresponding to a 33% velocity increase (p < 0.001, Figure 5a). Android (Free)https://play.google.com/store/apps/details?id=com.nickzom.nickzomcalculator